The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths? (mp = 1.00727u me = 0.00055u)
Solution
${\lambda _e} = {{12.27} \over {\sqrt V }}\mathop A\limits^o$<br><br>${\lambda _p} = {{0.286} \over {\sqrt V }}\mathop A\limits^o$<br><br>${{{\lambda _e}} \over {{\lambda _p}}} = {{12.27} \over {0.286}} = 43$
About this question
Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: de Broglie Hypothesis
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