An electron having de-Broglie wavelength $\lambda$ is incident on a target in a X-ray tube. Cut-off wavelength of emitted X-ray is :
Solution
$\lambda = {h \over {mv}}$<br><br>kinetic energy, $${{{P^2}} \over {2m}} = {{{h^2}} \over {2m{\lambda ^2}}} = {{hc} \over {{\lambda _c}}}$$<br><br>${\lambda _c} = {{2mc{\lambda ^2}} \over h}$
About this question
Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: Photoelectric Effect
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