What will be the most suitable combination of three resistors A = 2$\Omega$, B = 4$\Omega$, C = 6$\Omega$ so that $\left( {{{22} \over 3}} \right)$$\Omega$ is equivalent resistance of combination?
Solution
<p>${R_{eq}} = {{2 \times 4} \over {2 + 6}} + 6 = {{22} \over 3}$</p>
<p>$\Rightarrow$ A and B are in parallel and C is in series.</p>
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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