A resistor develops 300 J of thermal energy in 15 s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10 s is ____________ J.
Answer (integer)
450
Solution
<p>$300 = {I^2}R \times 15$</p>
<p>$\Rightarrow R = 5\,\Omega$</p>
<p>Now $I_2^2R{t_2}$</p>
<p>$= 9 \times 5 \times 10$</p>
<p>$= 450\,J$</p>
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Electrical Power
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