For full scale deflection of total 50 divisions, 50 mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2 div/mA will be :
Solution
${I_{\max }} = {{50} \over 2} = 25$ mA<br><br>$R = {V \over I} = {{50mV} \over {25mA}} = 2\Omega$
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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