A resistor dissipates 192 J of energy in 1s when a current of 4A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5s in _________ J.
Answer (integer)
3840
Solution
E = i<sup>2</sup>Rt<br><br>192 = 16 (R) (1)<br><br>R = 12$\Omega$<br><br>E<sub>1</sub> = (8)<sup>2</sup> (12) (5)<br><br>= 3840 J
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Electrical Power
This question is part of PrepWiser's free JEE Main question bank. 120 more solved questions on Current Electricity are available — start with the harder ones if your accuracy is >70%.