Easy MCQ +4 / -1 PYQ · JEE Mains 2022

Given below are two statements :

Statement I : A uniform wire of resistance $80 \,\Omega$ is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be $5 \,\Omega$.

Statement II: Two resistances 2R and 3R are connected in parallel in a electric circuit. The value of thermal energy developed in 3R and 2R will be in the ratio $3: 2$.

In the light of the above statements, choose the most appropriate answer from the option given below

  1. A Both statement I and statement II are correct
  2. B Both statement I and statement II are incorrect
  3. C Statement I is correct but statement II is incorrect Correct answer
  4. D Statement I is incorrect but statement II is correct

Solution

<p>Statement I : ${R_{1\,part}} = {{80} \over 4} = 20\,\Omega$</p> <p>$\Rightarrow {R_{eff}} = {{20} \over 4} = 5\,\Omega$</p> <p>Statement II : Ratio $= {{{{{{(\Delta V)}^2}} \over {3R}}} \over {{{{{(\Delta V)}^2}} \over {2R}}}}$</p> <p>$= {2 \over 3}$</p>

About this question

Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance

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