Ratio of thermal energy released in two resistors R and 3R connected in parallel in an electric circuit is :
Solution
For parallel connection, potential difference is same $(v)$
<br/><br/>
$$
\begin{aligned}
& P_{1}=\left(\frac{v^{2}}{R_{1}}\right) \\\\
& P_{2}=\left(\frac{v^{2}}{R_{2}}\right) \\\\
& \frac{P_{1}}{P_{2}}=\frac{H_{1}}{H_{2}}=\left(\frac{R_{2}}{R_{1}}\right)=\frac{3 R}{R}=(3: 1)
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Electrical Power
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