Resistance of the wire is measured as 2 $\Omega$ and 3 $\Omega$ at 10$^\circ$C and 30$^\circ$C respectively. Temperature co-efficient of resistance of the material of the wire is :
Solution
<p>R<sub>10</sub> = 2 = R<sub>0</sub>(1 + $\alpha$ $\times$ 10)</p>
<p>R<sub>30</sub> = 3 = R<sub>0</sub>(1 + $\alpha$ $\times$ 30)</p>
<p>On solving</p>
<p>$\alpha$ = 0.033/$^\circ$C
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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