The $\mathrm{H}$ amount of thermal energy is developed by a resistor in $10 \mathrm{~s}$ when a current of $4 \mathrm{~A}$ is passed through it. If the current is increased to $16 \mathrm{~A}$, the thermal energy developed by the resistor in $10 \mathrm{~s}$ will be :
Solution
$H \propto i^{2}$ for $t=$ constant
<br/><br/>$\Rightarrow$ $\frac{H}{H^{\prime}}=\left(\frac{4}{16}\right)^{2}$
<br/><br/>$\Rightarrow$ $H^{\prime}=16 H$
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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