Easy MCQ +4 / -1 PYQ · JEE Mains 2024

An electric toaster has resistance of $60 \Omega$ at room temperature $\left(27^{\circ} \mathrm{C}\right)$. The toaster is connected to a $220 \mathrm{~V}$ supply. If the current flowing through it reaches $2.75 \mathrm{~A}$, the temperature attained by toaster is around : ( if $\alpha=2 \times 10^{-4}$/$^\circ \mathrm{C}$)

  1. A 1235 $^\circ$C
  2. B 1667 $^\circ$C
  3. C 694 $^\circ$C
  4. D 1694 $^\circ$C Correct answer

Solution

<p>$$\begin{aligned} & \mathrm{R}_{\mathrm{T}-27}=60 \Omega, R_T=\frac{220}{2.75}=80 \Omega \\ & \mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T}) \\ & 80=60\left[1+2 \times 10^{-4}(\mathrm{~T}-27)\right] \\ & \mathrm{T} \approx 1694^{\circ} \mathrm{C} \end{aligned}$$</p>

About this question

Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance

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