The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by $50 \%$. The percentage change in voltage sensitivity of the galvanometer will be :
Solution
Current sensitivity $=$ Voltage sensitivity $\times R$
<br/><br/>Current sensitivity is made $1.5$ times.
<br/><br/>$R$ also increase $1.5$ times.
<br/><br/>Hence voltage sensitivity $=\frac{1.5 \times \text { current sensitivity }}{1.5 \times R}$
<br/><br/>$=\text { no change }$
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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