The atomic mass of ${ }_6 \mathrm{C}^{12}$ is $12.000000 \mathrm{~u}$ and that of ${ }_6 \mathrm{C}^{13}$ is $13.003354 \mathrm{~u}$. The required energy to remove a neutron from ${ }_6 \mathrm{C}^{13}$, if mass of neutron is $1.008665 \mathrm{~u}$, will be :
Solution
<p>$$\begin{aligned}
& { }_6 \mathrm{C}^{13}+\text { Energy } \rightarrow{ }_6 \mathrm{C}^{12}+{ }_0 \mathrm{n}^1 \\
& \Delta \mathrm{m}=(12.000000+1.008665)-13.003354 \\
& =-0.00531 \mathrm{u} \\
& \therefore \text { Energy required }=0.00531 \times 931.5 \mathrm{~MeV} \\
& =4.95 \mathrm{~MeV}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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