The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is :
Solution
<p>$\frac{1}{2}|P E|=K E$ for each value of $\mathrm{n}$ (orbit)</p>
<p>$\therefore \frac{K E}{|P E|}=\frac{1}{2}$</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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