Consider the following radioactive decay process
$$_{84}^{218}A\buildrel \alpha \over \longrightarrow {A_1}\buildrel {{\beta ^ - }} \over \longrightarrow {A_2}\buildrel \gamma \over \longrightarrow {A_3}\buildrel \alpha \over \longrightarrow {A_4}\buildrel {{\beta ^ + }} \over \longrightarrow {A_5}\buildrel \gamma \over \longrightarrow {A_6}$$
The mass number and the atomic number of A$_6$ are given by :
Solution
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow}{ }_{82}^{214} A_{4} \stackrel{\beta^{-}}{\longrightarrow}{ }_{83}^{214} A_{2} \stackrel{\gamma}{\longrightarrow}{ }_{83}^{214} A_{3} \stackrel{\alpha}{\longrightarrow}{ }_{81}^{210} A_{4} \stackrel{\beta^{+}}{\longrightarrow}{ }_{80}^{210} A_{5} \stackrel{\gamma}{\longrightarrow}{ }_{80}^{210} A_{6}$<br/><br/> Mass number $=210$
<br/><br/>
Atomic number $=80$
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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