A radioactive element $_{92}^{242}$X emits two $\alpha$-particles, one electron and two positrons. The product nucleus is represented by $_{\mathrm{P}}^{234}$Y. The value of P is __________.
Answer (integer)
87
Solution
${ }_{92}^{242} \mathrm{X} \stackrel{{ }^{2 \alpha}}{\longrightarrow}{ }_{88}^{234} \mathrm{~A} \stackrel{\mathrm{e}^{-}}{\longrightarrow}{ }_{89}^{234} \mathrm{~B} \stackrel{2 \mathrm{e}^{+}}{\longrightarrow}{ }_{87}^{234} \mathrm{Y}$<br/><br/>So, $P=87$
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Radioactivity
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