"Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. The ratio ${{{N_1}} \over {{N_2}}}$ will be equal to :"

Question

Accepted Answer

"Let Half life of x = t

then half life of y = 2t

when 3 half life of y is completed then 6 half life of x is completed.

$\therefore$ Now x have = ${{{N_1}} \over {{2^6}}}$ nuclei

and y have = ${{{N_2}} \over {{2^3}}}$ nuclei

From question,

${{{N_1}} \over {{2^6}}} = {{{N_2}} \over {{2^3}}}$

$\Rightarrow {{{N_1}} \over {{N_2}}} = 8$"

Two radioactive substances X and Y originally have N₁ and N₂ nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. The ratio ${{{N_1}} \over {{N_2}}}$ will be equal to :

Solution

About this question

Drill 25 more like these. Every day. Free.

Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. The ratio ${{{N_1}} \over {{N_2}}}$ will be equal to :

Solution

About this question

More Atoms and Nuclei questions

Drill 25 more like these. Every day. Free.

Two radioactive substances X and Y originally have N₁ and N₂ nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. The ratio ${{{N_1}} \over {{N_2}}}$ will be equal to :