Given below are two statements: one is labelled as Assertion $\mathbf{A}$ and the other is labelled as Reason $\mathbf{R}$
Assertion A: The nuclear density of nuclides ${ }_{5}^{10} \mathrm{~B},{ }_{3}^{6} \mathrm{Li},{ }_{26}^{56} \mathrm{Fe},{ }_{10}^{20} \mathrm{Ne}$ and ${ }_{83}^{209} \mathrm{Bi}$ can be arranged as $\rho_{\mathrm{Bi}}^{\mathrm{N}}>\rho_{\mathrm{Fe}}^{\mathrm{N}}>\rho_{\mathrm{Ne}}^{\mathrm{N}}>\rho_{\mathrm{B}}^{\mathrm{N}}>\rho_{\mathrm{Li}}^{\mathrm{N}}$
Reason R: The radius $R$ of nucleus is related to its mass number $A$ as $R=R_{0} A^{1 / 3}$, where $R_{0}$ is a constant.
In the light of the above statements, choose the correct answer from the options given below
Solution
<p>$R = {R_0}{A^{{1 \over 3}}}$, using this</p>
<p>$$\rho = {M \over {{4 \over 3}\pi {R^3}}} = {{A{m_P}} \over {{4 \over 3}\pi R_0^3A}} = {{{m_P}} \over {{4 \over 3}\pi R_0^3}}$$</p>
<p>$\rho$ is independent of mass number.</p>
<p>$\therefore$ A is false</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Nuclear Binding Energy
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