A nucleus has mass number $A_1$ and volume $V_1$. Another nucleus has mass number $A_2$ and Volume $V_2$. If relation between mass number is $A_2=4 A_1$, then $\frac{V_2}{V_1}=$ __________.
Answer (integer)
4
Solution
<p>For a nucleus</p>
<p>Volume: $\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^3$</p>
<p>$$\begin{aligned}
& \mathrm{R}=\mathrm{R}_0(\mathrm{A})^{1 / 3} \\
& \mathrm{~V}=\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{A} \\
& \Rightarrow \frac{\mathrm{V}_2}{\mathrm{~V}_1}=\frac{\mathrm{A}_2}{\mathrm{~A}_1}=4
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Nuclear Binding Energy
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