How many alpha and beta particles are emitted when Uranium 92U238 decays to lead 82Pb206 ?
Solution
<p>$${}_{92}{U^{238}}\buildrel {} \over
\longrightarrow {}_{82}P{b^{206}} + x\left( {{}_2H{e^4}} \right) + {}_y\left( {{}_{ - 1}{\beta ^0}} \right)$$</p>
<p>$238 = 206 + 4x + 0$</p>
<p>$\Rightarrow 4x = 32 \Rightarrow x = 8$</p>
<p>also, $92 = 82 + 2x - y$</p>
<p>$y = 82 + 16 - 92 = 6$</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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