A photon is emitted in transition from n = 4 to n = 1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h = 4 $\times$ 10$^{-15}$ eVs) :
Solution
$\frac{h c}{\lambda}=+13.6 \mathrm{eV}\left[\frac{1}{1}-\frac{1}{4^{2}}\right]$
<br/><br/>
$$
\Rightarrow \frac{4 \times 10^{-15} \times 3 \times 10^{-8}}{\lambda}=13.6\left[\frac{15}{16}\right]
$$
<br/><br/>
$\lambda=94.1 \mathrm{~nm}$
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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