Medium MCQ +4 / -1 PYQ · JEE Mains 2020

The energy required to ionise a hydrogen like ion in its ground state is 9 Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state ?

  1. A 35.8 nm
  2. B 11.4 nm Correct answer
  3. C 8.6 nm
  4. D 24.2 nm

Solution

So, ionisation energy = (13.6 Z<sup>2</sup>) eV <br><br>= 9 $\times$ 13.6 eV <br><br>$${1 \over \lambda } = R{Z^2}\left( {{1 \over {{1^2}}} - {1 \over {{3^2}}}} \right)$$ <br><br>= 1.09 $\times$ 10<sup>7</sup> $\times$ 9 $\times$ ${8 \over 9}$ <br><br> = 11.4 nm

About this question

Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom

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