"The radius R of a nucleus of mass number A can be estimated by the formula R = (1.3 $\times$ 10–15)A1/3 m. It follows that the mass density of a nucleus is of the order of : (Mprot. $\cong$ Mneut $\simeq$ 1.67 $\times$ 10–27 kg)"

Question

Accepted Answer

"$R = (1.3 \times {10^{ - 15}}){A^{{1 \over 3}}}$

We know, $m = pV$

$\Rightarrow$ $p = {m \over V}$

$\Rightarrow$ $p = {{{m_p}A} \over {{4 \over 3}\pi {R^3}}}$

$p = {{{m_p}A} \over {{4 \over 3}\pi \times {{(1.3 \times {{10}^{ - 15}})}^3}A}}$

$p \approx {10^{17}}kg/m$"

The radius R of a nucleus of mass number A can be estimated by the formula
R = (1.3 $\times$ 10^–15)A^1/3 m.
It follows that the mass density of a nucleus is of the order of :

(M_prot. $\cong$ M_neut $\simeq$ 1.67 $\times$ 10^–27 kg)

Solution

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The radius R of a nucleus of mass number A can be estimated by the formula R = (1.3 $\times$ 10–15)A1/3 m. It follows that the mass density of a nucleus is of the order of : (Mprot. $\cong$ Mneut $\simeq$ 1.67 $\times$ 10–27 kg)

Solution

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More Atoms and Nuclei questions

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The radius R of a nucleus of mass number A can be estimated by the formula
R = (1.3 $\times$ 10^–15)A^1/3 m.
It follows that the mass density of a nucleus is of the order of :

(M_prot. $\cong$ M_neut $\simeq$ 1.67 $\times$ 10^–27 kg)