"The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 $\times$ 10-16 s. The frequency of revolution of the electron in its first excited state (in s-1) is :"

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Accepted Answer

"Time period of revolution of electron in n^th orbit

V = ${{2\pi r} \over V}$

= $${{2\pi {a_0}\left( {{{{n^2}} \over Z}} \right)} \over {{V_0}\left( {{Z \over n}} \right)}}$$

$\Rightarrow$ T $\propto$ ${{{{n^3}} \over {{Z^2}}}}$

$\therefore$ ${{{T_1}} \over {{T_2}}} = {{n_1^3} \over {n_2^3}}$

$\Rightarrow$ ${{1.6 \times {{10}^{ - 16}}} \over {{T_2}}} = {1 \over {{{\left( 2 \right)}^3}}}$

$\Rightarrow$ T₂ = 1.6 $\times$ 8 $\times$ 10^-16

$\therefore$ f₂ = ${1 \over {{T_2}}}$ = ${1 \over {1.6 \times 8 \times {{10}^{ - 16}}}}$ = 7.8 $\times$ 10¹⁴"

The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 $\times$ 10^-16 s. The frequency of revolution of the electron in its first excited state (in s^-1) is :

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The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 $\times$ 10-16 s. The frequency of revolution of the electron in its first excited state (in s-1) is :

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The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.6 $\times$ 10^-16 s. The frequency of revolution of the electron in its first excited state (in s^-1) is :