In a reactor, 2 kg of ₉₂U²³⁵ fuel is fully used up in 30 days. The energy released per fission is 200 MeV. Given that the Avogadro number, N = 6.023 $\times$ 10²⁶ per kilo mole and 1 eV = 1.6 × 10^–19 J. The power output of the reactor is close to

Number of uranium atoms in 2 kg <br><br>= ${{2 \times 6.023 \times {{10}^{26}}} \over {235}}$ <br><br>Energy from one atom is 200 × 10⁶ e.V. hence total energy from 2 kg uranium <br><br>= ${{2 \times 6.023 \times {{10}^{26}}} \over {235}} \times 200 \times {10^6}$ eV <br><br>= ${{2 \times 6.023 \times {{10}^{26}}} \over {235}} \times 200 \times {10^6}$ $\times$ 1.6 × 10^–19 J <br><br>2 kg uranium is used in 30 days hence energy received per second or power is <br><br>Power = $${{2 \times 6.023 \times {{10}^{26}} \times 200 \times {{10}^6} \times 1.6 \times {{10}^{ - 19}}} \over {235 \times 30 \times 24 \times 3600}}$$ <br><br>= 63.2 × 10⁶ watt or 63.2 Mega Watt <br><br>$\simeq$ 60 MW