Medium MCQ +4 / -1 PYQ · JEE Mains 2020

Given the masses of various atomic particles
mp = 1.0072 u, mn = 1.0087 u, me = 0.000548 u,
${m_{\overline v }}$ = 0, md = 2.0141 u, where p $\equiv$ proton, n $\equiv$ neutron,
e $\equiv$ electron, $\overline v$ $\equiv$ antineutrino and d $\equiv$ deuteron. Which of the following process is allowed by momentum and energy conservation?

  1. A n + n $\to$ deuterium atom <br>(electron bound to the nucleus)
  2. B n + p $\to$ d + $\gamma$ Correct answer
  3. C p $\to$ n + e<sup>+</sup> + $\overline v$
  4. D e<sup>+</sup> + e<sup>-</sup> $\to$ $\gamma$

Solution

n + n $\to$ deuterium atom (This is incorrect) <br><br>Correct is n + p $\to$ d + $\gamma$ <br><br>p $\to$ n + e<sup>+</sup> + $\overline v$ <br>(This is incorrect as mass is increasing) <br><br>e<sup>+</sup> + e<sup>-</sup> $\to$ $\gamma$ (This is incorrect) <br><br>Correct is e<sup>+</sup> + e<sup>-</sup> $\to$ 2$\gamma$

About this question

Subject: Physics · Chapter: Atoms and Nuclei · Topic: Nuclear Binding Energy

This question is part of PrepWiser's free JEE Main question bank. 184 more solved questions on Atoms and Nuclei are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →