The energy equivalent of $1 \mathrm{~g}$ of substance is :
Solution
<p>To determine the energy equivalent of a mass, we use Einstein's mass-energy equivalence principle given by the equation:</p>
<p>$E = mc^2$</p>
<p>where:</p>
<p>- $E$ is the energy</p>
<p>- $m$ is the mass</p>
<p>- $c$ is the speed of light in a vacuum, which is approximately $3 \times 10^8 \mathrm{~m/s}$</p>
<p>Given the mass $m = 1 \mathrm{~g} = 1 \times 10^{-3} \mathrm{~kg}$, we can substitute these values into the equation:</p>
<p>$E = (1 \times 10^{-3} \mathrm{~kg}) \times (3 \times 10^8 \mathrm{~m/s})^2$</p>
<p>Calculating this, we get:</p>
<p>$E = 1 \times 10^{-3} \times 9 \times 10^{16}$</p>
<p>$E = 9 \times 10^{13} \mathrm{~J}$</p>
<p>Next, to convert this energy into electron volts ($\mathrm{eV}$), we use the conversion factor: $1 \mathrm{~J} = 6.242 \times 10^{12} \mathrm{~MeV}$.</p>
<p>Therefore:</p>
<p>$E = 9 \times 10^{13} \mathrm{~J} \times 6.242 \times 10^{12} \mathrm{~MeV/J}$</p>
<p>Calculating this, we get:</p>
<p>$E = 5.6178 \times 10^{26} \mathrm{~MeV}$</p>
<p>Therefore, the energy equivalent of $1 \mathrm{~g}$ of a substance is:</p>
<p><b>Option A:</b> $5.6 \times 10^{26} \mathrm{~MeV}$</p>
About this question
Subject: Physics · Chapter: Atoms and Nuclei · Topic: Bohr's Model of Hydrogen Atom
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