"Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of"

Question

Accepted Answer

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$\therefore$ $R = {R_0}{A^{{1 \over 3}}}$

$$ \Rightarrow {{{R_1}} \over {{R_2}}} = {\left( {{{{A_1}} \over {{A_2}}}} \right)^{{1 \over 3}}} = {\left( {{4 \over 3}} \right)^{{1 \over 3}}}$$

$\therefore$ Density ratio, ${{{\rho _1}} \over {{\rho _2}}} = {{{A_1}/{V_1}} \over {{A_2}/{V_2}}}$

$$ = \left( {{{{A_1}} \over {{A_2}}}} \right) \times {\left( {{{{R_2}} \over {{R_1}}}} \right)^3}$$

$= 1:1$

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Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of