If vectors $\overrightarrow {{a_1}} = x\widehat i - \widehat j + \widehat k$ and $\overrightarrow {{a_2}} = \widehat i + y\widehat j + z\widehat k$ are collinear, then a possible unit vector parallel to the vector $x\widehat i + y\widehat j + z\widehat k$ is :
Solution
$\overrightarrow {{a_2}} = \lambda \overrightarrow {{a_1}}$<br><br>$$\widehat i + y\widehat j + z\widehat k = \lambda (x\widehat i - \widehat j + \widehat k)$$<br><br>$1 = \lambda x,y = - \lambda ,z = \lambda$<br><br>$$x\widehat i + y\widehat j + z\widehat k = {1 \over \lambda }\widehat i - \lambda \widehat j + \lambda \widehat k$$<br><br>Unit vector $$ = {{{1 \over \lambda }\widehat i - \lambda \widehat j + \lambda \widehat k} \over {\sqrt {{1 \over {{\lambda ^2}}} + {\lambda ^2} + {\lambda ^2}} }}$$<br><br>$$ = {{\widehat i - {\lambda ^2}\widehat j + {\lambda ^2}\widehat k} \over {\sqrt {1 + 2{\lambda ^4}} }}$$<br><br>Let ${\lambda ^2} = 1$, possible unit vector $= {{\widehat i - \widehat j + \widehat k} \over {\sqrt 3 }}$
About this question
Subject: Mathematics · Chapter: Vector Algebra · Topic: Types of Vectors
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