Medium MCQ +4 / -1 PYQ · JEE Mains 2021

If vectors $\overrightarrow {{a_1}} = x\widehat i - \widehat j + \widehat k$ and $\overrightarrow {{a_2}} = \widehat i + y\widehat j + z\widehat k$ are collinear, then a possible unit vector parallel to the vector $x\widehat i + y\widehat j + z\widehat k$ is :

  1. A ${1 \over {\sqrt 3 }}\left( {\widehat i - \widehat j + \widehat k} \right)$ Correct answer
  2. B ${1 \over {\sqrt 2 }}\left( { - \widehat j + \widehat k} \right)$
  3. C ${1 \over {\sqrt 2 }}\left( {\widehat i - \widehat j} \right)$
  4. D ${1 \over {\sqrt 3 }}\left( {\widehat i + \widehat j - \widehat k} \right)$

Solution

$\overrightarrow {{a_2}} = \lambda \overrightarrow {{a_1}}$<br><br>$$\widehat i + y\widehat j + z\widehat k = \lambda (x\widehat i - \widehat j + \widehat k)$$<br><br>$1 = \lambda x,y = - \lambda ,z = \lambda$<br><br>$$x\widehat i + y\widehat j + z\widehat k = {1 \over \lambda }\widehat i - \lambda \widehat j + \lambda \widehat k$$<br><br>Unit vector $$ = {{{1 \over \lambda }\widehat i - \lambda \widehat j + \lambda \widehat k} \over {\sqrt {{1 \over {{\lambda ^2}}} + {\lambda ^2} + {\lambda ^2}} }}$$<br><br>$$ = {{\widehat i - {\lambda ^2}\widehat j + {\lambda ^2}\widehat k} \over {\sqrt {1 + 2{\lambda ^4}} }}$$<br><br>Let ${\lambda ^2} = 1$, possible unit vector $= {{\widehat i - \widehat j + \widehat k} \over {\sqrt 3 }}$

About this question

Subject: Mathematics · Chapter: Vector Algebra · Topic: Types of Vectors

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