Medium MCQ +4 / -1 PYQ · JEE Mains 2022

Let A, B, C be three points whose position vectors respectively are

$\overrightarrow a = \widehat i + 4\widehat j + 3\widehat k$

$$\overrightarrow b = 2\widehat i + \alpha \widehat j + 4\widehat k,\,\alpha \in R$$

$\overrightarrow c = 3\widehat i - 2\widehat j + 5\widehat k$

If $\alpha$ is the smallest positive integer for which $\overrightarrow a ,\,\overrightarrow b ,\,\overrightarrow c$ are noncollinear, then the length of the median, in $\Delta$ABC, through A is :

  1. A ${{\sqrt {82} } \over 2}$ Correct answer
  2. B ${{\sqrt {62} } \over 2}$
  3. C ${{\sqrt {69} } \over 2}$
  4. D ${{\sqrt {66} } \over 2}$

Solution

$\overrightarrow{A B} \| \overrightarrow{A C}$ if <br/><br/> $\frac{1}{2}=\frac{\alpha-4}{-6}=\frac{1}{2}$ <br/><br/> $\Rightarrow \alpha=1$ <br/><br/> $\vec{a}, \vec{b}, \vec{c}$ are non-collinear for $\alpha=2$ (smallest positive integer) <br/><br/> Mid point of $B C=M\left(\frac{5}{2}, 0, \frac{9}{2}\right)$ <br/><br/> $A M=\sqrt{\frac{9}{4}+16+\frac{9}{4}}=\frac{\sqrt{82}}{2}$

About this question

Subject: Mathematics · Chapter: Vector Algebra · Topic: Types of Vectors

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