Let the vectors $\overrightarrow a$, $\overrightarrow b$, $\overrightarrow c$
be such that
$\left| {\overrightarrow a } \right| = 2$, $\left| {\overrightarrow b } \right| = 4$
and $\left| {\overrightarrow c } \right| = 4$. If the projection of
$\overrightarrow b$
on $\overrightarrow a$
is equal to the projection of $\overrightarrow c$
on $\overrightarrow a$
and $\overrightarrow b$
is perpendicular to $\overrightarrow c$,
then the value of
$\left| {\overrightarrow a + \vec b - \overrightarrow c } \right|$
is ___________.
Answer (integer)
6
Solution
Projection of $\overrightarrow b$
on $\overrightarrow a$
= Projection of $\overrightarrow c$
on $\overrightarrow a$
<br><br>$\Rightarrow$ $${{\overrightarrow b .\overrightarrow a } \over {\left| {\overrightarrow a } \right|}} = {{\overrightarrow c .\overrightarrow a } \over {\left| {\overrightarrow a } \right|}}$$
<br><br>$\Rightarrow$ $\overrightarrow b .\overrightarrow a = \overrightarrow c .\overrightarrow a$
<br><br>$\because$ $\overrightarrow b$
is perpendicular to $\overrightarrow c$
<br><br>$\therefore$ $\overrightarrow b .\overrightarrow c = 0$
<br><br>Let $\left| {\overrightarrow a + \vec b - \overrightarrow c } \right|$ = k
<br><br>Square both sides
<br><br>k<sup>2</sup> = ${{{\left( {\overrightarrow a } \right)}^2}}$ + ${{{\left( {\overrightarrow b } \right)}^2}}$ + ${{{\left( {\overrightarrow c } \right)}^2}}$ + $2\overrightarrow a .\overrightarrow b$ - $2\overrightarrow b .\overrightarrow c$ - $2\overrightarrow a .\overrightarrow c$
<br><br>$\Rightarrow$ k<sup>2</sup> = ${{{\left( {\overrightarrow a } \right)}^2}}$ + ${{{\left( {\overrightarrow b } \right)}^2}}$ + ${{{\left( {\overrightarrow c } \right)}^2}}$
<br><br>$\Rightarrow$ k<sup>2</sup> = 2<sup>2</sup> + 4<sup>2</sup> + 4<sup>2</sup> = 36
<br><br>$\Rightarrow$ k = 6
About this question
Subject: Mathematics · Chapter: Vector Algebra · Topic: Types of Vectors
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