The equation of the plane which contains the y-axis and passes through the point (1, 2, 3) is :
Solution
Let the equation of the plane is a (x $-$ 1) + b(y $-$ 2) + c(z $-$ 3) = 0<br><br>Y-axis lies on it.<br><br>D.R.'s of y-axis are 0, 1, 0<br><br>$\therefore$ 0.a + 1.b + 0.c = 0 $\Rightarrow$ b = 0<br><br>$\therefore$ Equation of plane is a(x $-$ 1) + c(z $-$ 3) = 0<br><br>x = 0, z = 0 also satisfy it $-$a $-$3c = 0 $\Rightarrow$ a = $-$3c<br><br>$-$3c (x $-$ 1) + c (z $-$ 3) = 0<br><br>$-$3 + 3 + z $-$ 3 = 0<br><br>3x $-$ z = 0
About this question
Subject: Mathematics · Chapter: Three Dimensional Geometry · Topic: Direction Cosines and Ratios
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