Let a plane P pass through the point (3, 7, $-$7) and contain the line, ${{x - 2} \over { - 3}} = {{y - 3} \over 2} = {{z + 2} \over 1}$. If distance of the plane P from the origin is d, then d2 is equal to ______________.
Answer (integer)
3
Solution
$\overrightarrow {BA} = (\widehat i + 4\widehat j - 5\widehat k)$<br><br>$$\overrightarrow {BA} \times \overrightarrow l = \overrightarrow n = \left| {\matrix{
{\widehat i} & {\widehat j} & {\widehat k} \cr
{ - 3} & 2 & 1 \cr
1 & 4 & { - 5} \cr
} } \right|$$<br><br>$$a\widehat i + b\widehat j + c\widehat k = - 14\widehat i - \widehat j(14) + \widehat k( - 14)$$<br><br>a = 1, b = 1, c = 1<br><br>Plane is (x $-$ 2) + (y $-$ 3) + (z + 2) = 0<br><br>$\Rightarrow$ x + y + z $-$ 3 = 0<br><br>$\therefore$ d = $\sqrt 3$ $\Rightarrow$ d<sup>2</sup> = 3
About this question
Subject: Mathematics · Chapter: Three Dimensional Geometry · Topic: Direction Cosines and Ratios
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