Let P be the plane passing through the point (1, 2, 3) and the line of intersection of the planes $$\overrightarrow r \,.\,\left( {\widehat i + \widehat j + 4\widehat k} \right) = 16$$ and $$\overrightarrow r \,.\,\left( { - \widehat i + \widehat j + \widehat k} \right) = 6$$. Then which of the following points does NOT lie on P?
Solution
$(x + y + 4z - 16) + \lambda ( - x + y + z - 6) = 0$<br><br>Passes through (1, 2, 3)<br><br>$- 1 + \lambda ( - 2) \Rightarrow \lambda = - {1 \over 2}$<br><br>$2(x + y + 4z - 16) - ( - x + y + z - 6) = 0$<br><br>$3x + y + 7z - 26 = 0$
About this question
Subject: Mathematics · Chapter: Three Dimensional Geometry · Topic: Direction Cosines and Ratios
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