Let $\mathrm{A}=\{1,2,3,4,5,6,7\}$. Then the relation $\mathrm{R}=\{(x, y) \in \mathrm{A} \times \mathrm{A}: x+y=7\}$ is :
Solution
Here, $A=\{1,2,3,4,5,6,7\}$
<br/><br/>Since, $x+y=7 \Rightarrow y=7-x$
<br/><br/>So, $\mathrm{R}=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$
<br/><br/>$\because(a, b) \in \mathrm{R} \Rightarrow(b, a) \in \mathrm{R}$
<br/><br/>$\therefore \mathrm{R}$ is symmetric only.
About this question
Subject: Mathematics · Chapter: Sets, Relations and Functions · Topic: Sets and Operations
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