Let f, g : N $\to$ N such that f(n + 1) = f(n) + f(1) $\forall$ n$\in$N and g be any arbitrary function. Which of the following statements is NOT true?
Solution
$f(n + 1) = f(n) + 1$<br><br>$f(2) = 2f(1)$<br><br>$f(3) = 3f(1)$<br><br>$f(4) = 4f(1)$<br><br>.....<br><br>$f(n) = nf(1)$<br><br>$f(x)$ is one-one
About this question
Subject: Mathematics · Chapter: Sets, Relations and Functions · Topic: Sets and Operations
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