Which of the following is not correct for relation R on the set of real numbers ?
Solution
Note that (a, b) and (b, c) satisfy 0 < |x $-$ y| $\le$ 1 but (a, c) does not satisfy it so 0 $\le$ |x $-$ y| $\le$ 1 is symmetric but not transitive.
<br><br>For example,
<br><br>x = 0.2, y = 0.9, z = 1.5
<br><br>0 ≤ |x – y| = 0.7 ≤ 1
<br><br>0 ≤ |y – z| = 0.6 ≤ 1
<br><br>But |x – z| = 1.3 > 1
<br><br>So, (b) is correct.
About this question
Subject: Mathematics · Chapter: Sets, Relations and Functions · Topic: Sets and Operations
This question is part of PrepWiser's free JEE Main question bank. 195 more solved questions on Sets, Relations and Functions are available — start with the harder ones if your accuracy is >70%.