The domain of $$f(x) = {{{{\log }_{(x + 1)}}(x - 2)} \over {{e^{2{{\log }_e}x}} - (2x + 3)}},x \in \mathbb{R}$$ is
Solution
$x-2>0 \Rightarrow x>2$
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$\mathrm{x}+1>0 \Rightarrow \mathrm{x}>-1$
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$x+1 \neq 1 \Rightarrow x \neq 0$ and $x>0$
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Denominator
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$\mathrm{x}^{2}-2 \mathrm{x}-3 \neq 0$
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$(x-3)(x+1) \neq 0$
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$\mathrm{x} \neq-1,3$
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So Ans $(2, \infty)-\{3\}$
About this question
Subject: Mathematics · Chapter: Sets, Relations and Functions · Topic: Sets and Operations
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