If A = {x $\in$ R : |x $-$ 2| > 1},
B = {x $\in$ R : $\sqrt {{x^2} - 3}$ > 1},
C = {x $\in$ R : |x $-$ 4| $\ge$ 2} and Z is the set of all integers, then the number of subsets of the
set (A $\cap$ B $\cap$ C)c $\cap$ Z is ________________.
Answer (integer)
256
Solution
A = ($-$$\infty$, 1) $\cup$ (3, $\infty$)<br><br>B = ($-$$\infty$, $-$2) $\cup$ (2, $\infty$)<br><br>C = ($-$$\infty$, 2] $\cup$ [6, $\infty$)<br><br>So, A $\cap$ B $\cap$ C = ($-$$\infty$, $-$2) $\cup$ [6, $\infty$)<br><br>z $\cap$ (A $\cap$ B $\cap$ C)' = {$-$2, $-$1, 0, $-$1, 2, 3, 4, 5}<br><br>Hence, no. of its subsets = 2<sup>8</sup> = 256.
About this question
Subject: Mathematics · Chapter: Sets, Relations and Functions · Topic: Sets and Operations
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