If the 3rd term of a GP is 12 and the 6th term is 96, then the common ratio is:
Solution
a₃ = ar² = 12; a₆ = ar⁵ = 96. Dividing: ar⁵/ar² = r³ = 96/12 = 8 → r = 2.
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Geometric Progression
This question is part of PrepWiser's free JEE Main question bank. 16 more solved questions on Sequences and Series are available — start with the harder ones if your accuracy is >70%.