A random variable X has the following probability distribution :
| X | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| P(X) | k | 2k | 4k | 6k | 8k |
The value of P(1 < X < 4 | X $\le$ 2) is equal to :
Solution
<p>$\because$ x is a random variable</p>
<p>$\therefore$ $k + 2k + 4k + 6k + 8k = 1$</p>
<p>$\therefore$ $k = {1 \over {21}}$</p>
<p>Now, $P(1 < x < 4\,|\,x \le 2) = {{4k} \over {7k}} = {4 \over 7}$</p>
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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