If an unbiased die, marked with $-2,-1,0,1,2,3$ on its faces, is thrown five times, then the probability that the product of the outcomes is positive, is :
Solution
<p>${}^5{C_0} \times {3^5} = 243$</p>
<p>${}^5{C_2} \times {2^2} \times {3^3} = 1080$</p>
<p>${}^5{C_4} \times {2^4}\,.\,3 = 240$</p>
<p>$\therefore$ required probability</p>
<p>$$ = {{243 + 1080 + 240} \over {6 \times 6 \times 6 \times 6 \times 6}} = {{521} \over {2592}}$$</p>
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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