When a missile is fired from a ship, the probability that it is intercepted is ${1 \over 3}$ and the probability that the missile hits the target, given that it is not intercepted, is ${3 \over 4}$. If three missiles are fired independently from the ship, then the probability that all three hit the target, is :
Solution
Probability of not getting intercepted = ${2 \over 3}$<br><br>When it is not intercepted, probability of missile hitting target = ${3 \over 4}$<br><br>$\therefore$ So when such 3 missiles launched
then P (all 3 hitting the target)
<br><br>= ${\left( {{2 \over 3} \times {3 \over 4}} \right)}$ $\times$ ${\left( {{2 \over 3} \times {3 \over 4}} \right)}$ $\times$ ${\left( {{2 \over 3} \times {3 \over 4}} \right)}$
<br><br>$= {1 \over 8}$
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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