The probability of selecting integers a$\in$[$-$ 5, 30] such that x2 + 2(a + 4)x $-$ 5a + 64 > 0, for all x$\in$R, is :
Solution
D < 0<br><br>$\Rightarrow$ 4(a + 4)<sup>2</sup> $-$ 4($-$5a + 64) < 0<br><br>$\Rightarrow$ a<sup>2</sup> + 16 + 8a + 5a $-$ 64 < 0<br><br>$\Rightarrow$ a<sup>2</sup> + 13a $-$ 48 < 0<br><br>$\Rightarrow$ (a + 16) (a $-$ 3) < 0<br><br>$\Rightarrow$ a $\in$ ($-$16, 3)<br><br>$\therefore$ Possible a : {$-$5, $-$4, ............., 3}<br><br>$\therefore$ Required probability = ${8 \over {36}}$ = ${2 \over {9}}$
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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