"Three dice are rolled. If the probability of getting different numbers on the three dice is $\frac{p}{q}$, where $p$ and $q$ are co-prime, then $q-p$ is equal to :"

Question

Accepted Answer

"Total number of outcomes $=6 \times 6 \times 6=216$

Number of outcomes getting different numbers on the three dice are ${ }^6 P_3=\frac{6 !}{3 !}=120$

$\therefore$ Required probability $=\frac{120}{216}=\frac{5}{9}$

$\therefore p=5$ and $q=9$

$\therefore q-p=9-5=4$"

Three dice are rolled. If the probability of getting different numbers on the three dice is $\frac{p}{q}$, where $p$ and $q$ are co-prime, then $q-p$ is equal to :

Solution

About this question

Drill 25 more like these. Every day. Free.

Three dice are rolled. If the probability of getting different numbers on the three dice is $\frac{p}{q}$, where $p$ and $q$ are co-prime, then $q-p$ is equal to :

Solution

About this question

More Probability questions

Drill 25 more like these. Every day. Free.