Let S be the set of all the words that can be formed by arranging all the letters of the word GARDEN. From the set S, one word is selected at random. The probability that the selected word will NOT have vowels in alphabetical order is:
Solution
<p>A, E,G R D N</p>
<p>$$\text { Probabllity }(\mathrm{P})=\frac{\text { favourable case }}{\text { Total case }}$$</p>
<p>(when A & E are in order)</p>
<p>Total case $=6$ !</p>
<p>Favourable case $={ }^6 \mathrm{C}_2 .4$ !</p>
<p>$P=\frac{(15) 4!}{(30) 4!}$</p>
<p>Probablity when not in order $=1-\frac{1}{2}=\frac{1}{2}$</p>
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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