A dice is thrown two times and the sum of the scores appearing on the die is observed to be a multiple of 4. Then the conditional probability that the score 4 has appeared atleast once is :
Solution
Let A is the event for getting score a multiple
of 4.
<br><br>So, A = { (1, 3), (3, 1), (2, 2), (2, 6), (6, 2),
(3, 5), (5, 3), (4, 4), (6, 6) } = 09
<br><br>n(A) = 9
<br><br>B : Score of 4 has appeared at least once.
<br><br>B = {(4, 4)}
<br><br>So, Required probability = ${1 \over 9}$
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
This question is part of PrepWiser's free JEE Main question bank. 143 more solved questions on Probability are available — start with the harder ones if your accuracy is >70%.