Two integers $x$ and $y$ are chosen with replacement from the set $\{0,1,2,3, \ldots, 10\}$. Then the probability that $|x-y|>5$, is :
Solution
<p>If $x=0, y=6,7,8,9,10$</p>
<p>If $x=1, y=7,8,9,10$</p>
<p>If $x=2, y=8,9,10$</p>
<p>If $x=3, y=9,10$</p>
<p>If $x=4, y=10$</p>
<p>If $x=5, y=$ no possible value</p>
<p>Total possible ways $=(5+4+3+2+1) \times 2$</p>
<p>$=30$</p>
<p>Required probability $=\frac{30}{11 \times 11}=\frac{30}{121}$</p>
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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