Two dies are rolled. If both dices have six faces numbered 1, 2, 3, 5, 7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is :
Solution
n(S) = 36<br><br>possible ordered pair :
<br><br> (1, 1), (1, 2), (1, 3), (1, 5), (1, 7), <br>(2, 1), (2, 2), (2, 3), (2, 5), <br>(3, 1), (3, 2), (3, 3), (3, 5), <br>(5, 1), (5, 2), (5, 3), <br>(7, 1)<br><br>Number of favourable outcomes = 17<br><br>Probability = ${{17} \over {36}}$
About this question
Subject: Mathematics · Chapter: Probability · Topic: Classical and Axiomatic Probability
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