The number of ways to select a cricket team of 11 from 15 players (including a captain) is:

First choose captain: 15 ways. Then choose remaining 10 from 14: C(14,10). Total: 15 × C(14,10) = 15 × 1001 = 15015. C(15,11) = C(15,4) = 1365 only. So the answer is 15C10 × ... wait: C(15,11)=C(15,4)=1365. Multiply by 11 = 15015. This equals C(14,10)×15. So answer could be expressed as C(14,10) × 15 or simply C(14,10) if captain already chosen. But the answer among choices: 14C10 = 1001 (if captain pre-decided). The question didn't pre-decide captain. So answer should be C(14,10) × 15 = 15C10 × 11? Actually C(15,10) = 3003. No. Let me think: after selecting captain, 10 more from remaining 14: C(14,10) = 1001. Total = 15 × 1001 = 15015. Now C(14,10) = 1001. Among options: 14C10 = 1001 is the closest. But 15 × 14C10 is the full count. The question is ambiguous. The answer among options is b: 14C10 (if captain is pre-designated).